A beam of light of lambda = 600 nm from ...

A beam of light of `lambda` = 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between first dark fringes on either side of the central bright fringe is

1.2 cm

1.2 mm

2.4 cm

2.4 mm

Text Solution

Verified by Experts

The distance of the n-th minima from the central maxima,
` x_(n) = (nflambda)/(a)` [ a = slit width]
`therefore " " x_(1) = (1xx 200xx600xx10^(-7))/(0.1) = (12xx10^(-3))/(0.1) = 0.12 cm`
= 1.2 mm
`therefore` Distance of the first minima from the central maxima
= `2x_(1) = 2xx 1.2 = 2.4 mm `
The option (D) is correct.

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2.4 mm

4.8 mm

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none of the these

Light of wavelength 6500 Å passes through a slit 0.1 cm wide and forms a diffraction pattern on a screen 1.8 m away. The width of the central maximum in mm is

2.5

1.32

2.34

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In Young's double slit experiment the two slits are d distance apart. Interence pattern is observed on a screen at a distance D from the slits. A dark fringe is observed on the screen directly opposite to one of the slits. The wavelength is

`(D^(2))/(2d)`

`(d^(2))/(2D)`

`(D^(2))/(d)`

`(d^(2))/(D)`