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Electron of a hydrogen atom revolves in ...

Electron of a hydrogen atom revolves in 3rd orbit.
Find the angular momentum of the electron.
`(h=6.6xx10^(-27) erg*s)`

Text Solution

Verified by Experts

Principal quantum number of 3rd Bohr orbit, n=3 . So according to Bohr's postulate, angular momentum of eletron in the orbit,
`L_3=3xxh/(2 pi) =(3xx6.6xx10^(-27))/(2xx (pi))=3.15xx10^(-27) erg*s`
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Knowledge Check

  • The orbital angular momentum of a 2p-electron is

    A
    `sqrt(3)h`
    B
    `sqrt(6)h`
    C
    zero
    D
    `sqrt(2)h/(2pi)`
  • The orbital angular momentum of p-electron is given by as

    A
    `h/(sqrt2pi)`
    B
    `sqrt3 (h/(2pi))`
    C
    `sqrt(3/2) h/pi`
    D
    `sqrt6(h/(2pi))`
  • What is the orbital angular momentum of an electron in 'f' orbital ?

    A
    `1.5h//pi`
    B
    `sqrt6h//pi`
    C
    `sqrt3h//pi`
    D
    `sqrt3h//2pi`
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