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Electron of a hydrogen atom revolves in ...

Electron of a hydrogen atom revolves in 3rd orbit.
Find the angular momentum of the electron.
`(h=6.6xx10^(-27) erg*s)`

Text Solution

Verified by Experts

Principal quantum number of 3rd Bohr orbit, n=3 . So according to Bohr's postulate, angular momentum of eletron in the orbit,
`L_3=3xxh/(2 pi) =(3xx6.6xx10^(-27))/(2xx (pi))=3.15xx10^(-27) erg*s`
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