Home
Class 12
PHYSICS
If the principal quantum number of an ...

If the principal quantum number of an energy state be n , the energy of a hydrogen atom, `E= -(13.6)/(n^2)eV`. Due to transition of electron from n=3 to n=2 level, what will be the energy of the photon emitted ?

Text Solution

Verified by Experts

The correct Answer is:
1.89 eV
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ATOM

    CHHAYA PUBLICATION|Exercise PROBLEM SET-II|4 Videos

  • ATOM

    CHHAYA PUBLICATION|Exercise PROBLEM SET-II (Hots numerical problems)|8 Videos

  • ATOM

    CHHAYA PUBLICATION|Exercise EXERCISE(Short Answer Type Questions-II)|2 Videos

  • ALTERNATING CURRENT

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|33 Videos

  • ATOMIC NUCLEUS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|14 Videos

Similar Questions

Explore conceptually related problems

The ionization energy of the hydrogen atom is 13.6eV. The potential energy of the electron in n=2 state of hydrogen atom is

The ground state energy of hydrogen atom is - 13.6 eV :- What does negative sign indicate?

Knowledge Check

  • Energy in the second energy state of hydrogen atom is E_2 . Then

    A
    energy in the third energy state of `He^(+)` ion (Z=2) is `4/9 E_2`
    B
    energy in the ground state `He^(+)` ion (Z=2) is `16 E_2`
    C
    energy in the third energy state of `Li^(2+)`ion (Z=3) is `4E_2`
    D
    energy in the second energy state of `Li^(2+)` ion (Z=3) is `9E_2`

  • Ground state energy of hydrogen atom is -13.6 eV . If the electron in this atom jumps from the fourth level to the second level, what will be the wavelength of the emitted radiation ?

    A
    2918 Å
    B
    1824 Å
    C
    4863 Å
    D
    3824 Å

  • If the 1st ionisation energy of H atom is 13.6 eV then the 2nd ionisation energy of He atom is

    A
    27.2eV
    B
    40.8eV
    C
    54.4eV
    D
    108.8eV

    • Similar Questions

    Explore conceptually related problems

    Calculate the ionisation energy of hydrogen atom as well as energy needed to promote its electron from first energy level to third energy level

    The ground state energy of hydrogen atom is -13.6 eV. what are the kinetic and potential energies of the electron in this state ?

    The ground state energy of hydrogen atom is - 13.6 eV :- What is the energy required to none an electron from ground state to 1st excited state to the atom?

    If the energy of an elctromin ground State of hydrogen atom be 13.6 ev then its ionisation potential is—

    The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?

    Home
    Profile