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The ionisation energy of hydrogen is 13....

The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released when an electron jumps from the first excited state (n=2) to the ground state of a hydrogen atom is

A

3.4 eV

B

4.53 eV

C

10.2 eV

D

13.6 eV

Text Solution

Verified by Experts

The correct Answer is:
B
Energy of the released photon
`=13.6 [(1)/(n_(i)^(2))-(1)/(n_(f)^(2)) ]=13.6 [1/(1^2)-1/(2^2)] =10.2 eV`
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Knowledge Check

  • As an electron makes a transition from an excited state to the ground state of a hydrogen -like atom / ion

    A
    its kinetic energy increases but potential energy and total energy decrease
    B
    kinetic energy , potential energy and total energy decrease
    C
    kinetic energy decreases, potential energy increases but total energy remains same
    D
    kinetic energy and total energy decrease but potential energy increase

  • The total energy of an electron in the ground state , of hydrogen atom is

    A
    zero
    B
    13.6 eV
    C
    `-13.6 eV`
    D
    `-13.6 J`

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