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The ionisation energy of hydrogen is 13....

The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released when an electron jumps from the first excited state (n=2) to the ground state of a hydrogen atom is

A

3.4 eV

B

4.53 eV

C

10.2 eV

D

13.6 eV

Text Solution

Verified by Experts

The correct Answer is:
B
Energy of the released photon
`=13.6 [(1)/(n_(i)^(2))-(1)/(n_(f)^(2)) ]=13.6 [1/(1^2)-1/(2^2)] =10.2 eV`
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