Given the value of Rydberg constant is `10^7m^(-1)`, the wave number of the last line of the Balmer series in hydrogen spectrum will be
A
`0.5xx10^(7)m^(-1)`
B
`0.25xx10^7m^(-1)`
C
`2.5xx10^7m^(-1)`
D
`0.025xx10^4m^(-1)`
Text Solution
Verified by Experts
The correct Answer is:
B
`1/lambda=R(1/(n_1^2)-1/(n_2^2))` `therefore` The wave number of the last line of the Balmer series, `barnu=1/lambda=10^7(1/2^2-1/oo^2)=0.25xx10^7m^(-1)`
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