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Given the value of Rydberg constant is 1...

Given the value of Rydberg constant is `10^7m^(-1)`, the wave number of the last line of the Balmer series in hydrogen spectrum will be

A

`0.5xx10^(7)m^(-1)`

B

`0.25xx10^7m^(-1)`

C

`2.5xx10^7m^(-1)`

D

`0.025xx10^4m^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`1/lambda=R(1/(n_1^2)-1/(n_2^2))`
`therefore` The wave number of the last line of the Balmer series,
`barnu=1/lambda=10^7(1/2^2-1/oo^2)=0.25xx10^7m^(-1)`
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Knowledge Check

  • The wave number of the first line in the Lyman series in hydrogen spectrum is

    A
    72755.5 `cm^(-1)`
    B
    109678 `cm^(-1)`
    C
    82258.5 `cm^(-1)`
    D
    65473.6`cm^(-1)`

  • The ratio of minimum wavelength of Lyman and Balmer series in hydrogen spectrum will be

    A
    10
    B
    5
    C
    0.25
    D
    1.25

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