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The tension in the string revolving in a...

The tension in the string revolving in a vertical circle with a mass m at the end which is at the lowest position

A

`(m v^(2))/(r)`

B

`(m v^(2))/(r)-mg`

C

`(m v^(2))/(r) + mg`

D

`mg`

Text Solution

Verified by Experts

The correct Answer is:
C
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A stone of mass 0.4 kg is tied to a string and rotated in a vertical circle of radius 1.2 m . Calculate the speed of the stone for which the tension in the string is zero at the highest point of the circle . What is the tension at the lowest point in this case ?

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Knowledge Check

  • IF a stone is tied to one end of the string and whirled in verticle circle, then the tension in the string at the lowest point is equal to

    A
    centripetal force
    B
    the difference between centripetal force and weight of the stone
    C
    the addition of the centripetal force and weight of the stone
    D
    weight of the stone

  • A stone of mass m tied to the end of a string revolves in a vertical circle of radius R. The net forces at the lowest and highest points of the circle directed vertically downwards are: [Choose the correct alternative] Lowest point Highest point T_(1) and V_(1) denote the tension and speed at the lowest point T_(2) and V_(2) denote the corresponding values at the highest points.

    A
    `mg-T_(1)mg+T_(2)`
    B
    `mg+T_(1)mg-T_(2)`
    C
    `mg+T_(1)-(mv_(1)^(2))//R mg-T+(mv_(1)^(2))//R`
    D
    `mg-T_(1)-(mv_(1)^(2))//Rmg+t_(2)+(mv_(1)^(2))//R`

  • A body of mass m tied to a string is moved in a vertical circle of radius r. The difference in tensions at the lowest point and the highest point is

    A
    2mg
    B
    6mg
    C
    4mg
    D
    8mg

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