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g(e) and g(p) denote the acceleration du...

`g_(e)` and `g_(p)` denote the acceleration due to gravity on the surface of the earth and another planet whose mass and radius are twice as that of earth. Then

A

`g_(p)=g_(e)`

B

`g_(p)=g_(e)//2`

C

`g_(p)=2g_(e)`

D

`g_(p)=g_(e)//4`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the relationship between the acceleration due to gravity on the surface of the Earth (denoted as \( g_e \)) and the acceleration due to gravity on the surface of another planet (denoted as \( g_p \)) whose mass and radius are both twice that of the Earth. ### Step-by-Step Solution: 1. **Understanding the Formula for Acceleration due to Gravity**: The acceleration due to gravity \( g \) on the surface of a planet is given by the formula: \[ g = \frac{G M}{R^2} \] where \( G \) is the universal gravitational constant, \( M \) is the mass of the planet, and \( R \) is the radius of the planet. 2. **Calculate \( g_e \) for Earth**: For Earth, we denote its mass as \( M_e \) and its radius as \( R_e \). Thus, the acceleration due to gravity on Earth is: \[ g_e = \frac{G M_e}{R_e^2} \] 3. **Determine the Mass and Radius of the New Planet**: The problem states that the mass and radius of the new planet are both twice that of Earth: \[ M_p = 2 M_e \] \[ R_p = 2 R_e \] 4. **Calculate \( g_p \) for the New Planet**: Now, we can find the acceleration due to gravity on the surface of the new planet: \[ g_p = \frac{G M_p}{R_p^2} \] Substituting the values of \( M_p \) and \( R_p \): \[ g_p = \frac{G (2 M_e)}{(2 R_e)^2} \] Simplifying the denominator: \[ g_p = \frac{G (2 M_e)}{4 R_e^2} \] 5. **Relate \( g_p \) to \( g_e \)**: Now we can express \( g_p \) in terms of \( g_e \): \[ g_p = \frac{2 G M_e}{4 R_e^2} = \frac{1}{2} \cdot \frac{G M_e}{R_e^2} = \frac{1}{2} g_e \] 6. **Final Relationship**: Therefore, the relationship between the acceleration due to gravity on the new planet and that on Earth is: \[ g_p = \frac{1}{2} g_e \] ### Conclusion: The acceleration due to gravity on the surface of the new planet is half that of the acceleration due to gravity on the surface of the Earth.
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Let g be the acceleration due to gravity on the earth's surface.

What will be the relation the acceleration due to gravity on the surface of the earth and on a planet respectively, whose mass and radius are twice that of the earth ?

Knowledge Check

  • If g_(1) and g_(2) denote acceleration due to gravity on the surface of the earth and on a planet whose mass and radius is thrice that of earth, then

    A
    `g_(1)=9g_(2)`
    B
    `g_(2)=9g_(1)`
    C
    `g_(1)=3g_(2)`
    D
    `g_(2)=3g_(1)`
  • A planet has a mass M_(1) and radius R_(1). The value of acceleration- due to gravity on its surface is g_(1). There is another planet 2, whose mass and radius both are two times that of the first planet. Which one of the following is the acceleration due to gravity on the surface of planet 2?

    A
    `g_(1)`
    B
    `2g_(1)`
    C
    `g_(1)//2`
    D
    `g_(1)//4`
  • If the acceleration due to gravity on the surface of earth is g, then the acceleration due to gravity on the surface of a planet whose mass is same as that of earth and radius is twice as that of earth is _________________.

    A
    g/4
    B
    g/2
    C
    4g
    D
    2g
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