We have three beakers A , B and C containing glycerine, water and kerosene respectively. They are stirred vigorously and placed on a table. The liquid which comes to rest at the earliest is

Options

A. Glycerine
B. Water level in Section A goes up and that in B comes down
C. Kerosene
D. All of them at the same time

Answer

To determine which liquid comes to rest the earliest after being stirred, we need to analyze the viscosity of each liquid involved: glycerine, water, and kerosene.

### Step-by-Step Solution:

1. **Understanding Viscosity**:
- Viscosity is a measure of a fluid's resistance to flow. It is determined by the intermolecular forces between the particles of the liquid. Higher viscosity means a greater resistance to flow and a slower return to rest after being disturbed.

2. **Identifying the Liquids**:
- We have three liquids:
- Beaker A: Glycerine
- Beaker B: Water
- Beaker C: Kerosene

3. **Comparing Viscosity**:
- Glycerine has a high viscosity because its molecules are strongly attracted to each other. This means it will resist flow and come to rest more slowly.
- Water has a moderate viscosity, less than that of glycerine, which means it will flow more easily and come to rest faster than glycerine.
- Kerosene has the lowest viscosity among the three. Its molecules are less attracted to each other, allowing it to flow freely and come to rest the quickest.

4. **Conclusion**:
- Since kerosene has the lowest viscosity, it will come to rest the earliest after being stirred. Therefore, the answer to the question is that kerosene will be the liquid that comes to rest first.

### Final Answer:
The liquid which comes to rest at the earliest is **kerosene** (Beaker C).