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In which of the following reactions is t...

In which of the following reactions is there a change in the oxidation number of nitrogen atom?

A

`2NO_(2)rarrN_(2)O_(4)`

B

`NH_(3)+H_(2)OrarrNH_(4)^(+)+OH^(-)`

C

`N_(2)O_(5)+H_(2)Orarr2HNO_(3)`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine if there is a change in the oxidation number of nitrogen in the given reactions, we will analyze each reaction step by step. ### Step 1: Analyze the first reaction: NO2 → N2O4 1. **Identify oxidation states**: - In NO2: - Oxygen (O) has an oxidation state of -2. - Let the oxidation state of nitrogen (N) be x. - The equation becomes: x + 2(-2) = 0 → x - 4 = 0 → x = +4. - In N2O4: - There are 2 nitrogen atoms, so the oxidation state of nitrogen remains the same. - The equation becomes: 2x + 4(-2) = 0 → 2x - 8 = 0 → 2x = 8 → x = +4. 2. **Conclusion**: The oxidation state of nitrogen is +4 in both NO2 and N2O4. - **Change in oxidation number**: No change. ### Step 2: Analyze the second reaction: NH3 → NH4+ 1. **Identify oxidation states**: - In NH3: - Hydrogen (H) has an oxidation state of +1. - Let the oxidation state of nitrogen (N) be y. - The equation becomes: y + 3(+1) = 0 → y + 3 = 0 → y = -3. - In NH4+: - The equation becomes: y + 4(+1) = +1 → y + 4 = 1 → y = -3. 2. **Conclusion**: The oxidation state of nitrogen is -3 in both NH3 and NH4+. - **Change in oxidation number**: No change. ### Step 3: Analyze the third reaction: N2O5 → HNO3 1. **Identify oxidation states**: - In N2O5: - Oxygen (O) has an oxidation state of -2. - Let the oxidation state of nitrogen (N) be z. - The equation becomes: 2z + 5(-2) = 0 → 2z - 10 = 0 → 2z = 10 → z = +5. - In HNO3: - Hydrogen (H) has an oxidation state of +1, and Oxygen (O) has an oxidation state of -2. - The equation becomes: z + 3(-2) + 1 = 0 → z - 6 + 1 = 0 → z - 5 = 0 → z = +5. 2. **Conclusion**: The oxidation state of nitrogen is +5 in both N2O5 and HNO3. - **Change in oxidation number**: No change. ### Final Conclusion After analyzing all the reactions, we find that there is no change in the oxidation number of nitrogen in any of the given reactions. Therefore, the answer is: **None of these reactions show a change in the oxidation number of nitrogen.** ---
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Knowledge Check

  • Oxidation number of nitrogen can be -

    A
    From + 5 to -3
    B
    From -5 to -3
    C
    From -5 to +3
    D
    From + 10 to +6
  • In which reaction, there is change in oxidation number of N atom?

    A
    `2NO_(2) iff N_(2)O_(4)`
    B
    `2NO_(2)+H_(2)O rarr HNO_(3)+HNO_(2)`
    C
    `NH_(4)OH rarr NH_(4)^(+)+OH^(-)`
    D
    `N_(2)O_(5)+H_(2)O rarr 2HNO_(3)`
  • Oxidation number of nitrogen in NaNO_(2) is

    A
    `+2`
    B
    `+4`
    C
    `+3`
    D
    `-3`
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