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Moles of K(2)Cr(2)O(7) used to oxidise 1...

Moles of `K_(2)Cr_(2)O_(7)` used to oxidise 1 mol `Fe_(0.92)O` to `Fe^(3+)` are :

A

`0.92/6`

B

`(70)/(92)xx1/6`

C

`0.76/6`

D

`(70)/(92)xx1/3`

Text Solution

Verified by Experts

The correct Answer is:
c
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Knowledge Check

  • Acidic K_(2) Cr_(2)O_(7) oxidises KI to

    A
    KOI
    B
    `KOI_(3)`
    C
    HI
    D
    `I_(2)`

  • The ratio of number of moles of KMnO_(4)" and "K_(2)Cr_(2)O_(7) required to oxidise 0.1 mol Sn^(2+)" to " Sn^(+4) in acidic medium

    A
    `6:5`
    B
    `5:6`
    C
    `1:2`
    D
    `2:1`

  • If equal volumes of 0.1 M KMnO_(4) and 0.1 M K_(2)Cr_(2)O_(7) solutions are allowed to oxidise Fe^(2+) to Fe^(3+) in acidic medium, then Fe^(2+) oxidised will be:

    A
    more by `KMnO_(4)`
    B
    more by `K_(2)CrO_(7)`
    C
    equal in both cases
    D
    can't be determined

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