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Same mass of glucose (C(6)H(12)O(6)) and...

Same mass of glucose `(C_(6)H_(12)O_(6))` and acetic acid `(CH_(3)COOH)` contain:

A

same number of carbon atoms

B

same number of hydrogen atoms

C

same number of oxygen atoms

D

all of the above

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of comparing the same mass of glucose \((C_6H_{12}O_6)\) and acetic acid \((CH_3COOH)\), we need to follow these steps: ### Step 1: Determine the Molar Mass of Glucose 1. **Calculate the molar mass of glucose**: - Carbon (C): 12 g/mol, and there are 6 carbon atoms. - Hydrogen (H): 1 g/mol, and there are 12 hydrogen atoms. - Oxygen (O): 16 g/mol, and there are 6 oxygen atoms. \[ \text{Molar mass of } C_6H_{12}O_6 = (6 \times 12) + (12 \times 1) + (6 \times 16) = 72 + 12 + 96 = 180 \text{ g/mol} \] ### Step 2: Determine the Molar Mass of Acetic Acid 2. **Calculate the molar mass of acetic acid**: - Carbon (C): 12 g/mol, and there are 2 carbon atoms. - Hydrogen (H): 1 g/mol, and there are 4 hydrogen atoms. - Oxygen (O): 16 g/mol, and there are 2 oxygen atoms. \[ \text{Molar mass of } CH_3COOH = (2 \times 12) + (4 \times 1) + (2 \times 16) = 24 + 4 + 32 = 60 \text{ g/mol} \] ### Step 3: Calculate the Number of Moles for Each Substance 3. **Calculate the number of moles for glucose and acetic acid**: - Let the mass of each substance be \( m \) grams. - The number of moles of glucose: \[ n_{C_6H_{12}O_6} = \frac{m}{180} \] - The number of moles of acetic acid: \[ n_{CH_3COOH} = \frac{m}{60} \] ### Step 4: Compare the Number of Moles 4. **Compare the number of moles**: - Since both substances have the same mass \( m \), we can compare the number of moles: \[ n_{C_6H_{12}O_6} = \frac{m}{180}, \quad n_{CH_3COOH} = \frac{m}{60} \] ### Step 5: Determine the Ratio of Moles 5. **Determine the ratio of moles**: - To find out how many moles of acetic acid are present compared to glucose: \[ \frac{n_{CH_3COOH}}{n_{C_6H_{12}O_6}} = \frac{\frac{m}{60}}{\frac{m}{180}} = \frac{180}{60} = 3 \] - This means that for the same mass, there are 3 times more moles of acetic acid than glucose. ### Conclusion Thus, the same mass of glucose and acetic acid contains different numbers of moles, with acetic acid having more moles than glucose.
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360 amu of Glucose (C_6H_12O_6) contains :

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Knowledge Check

  • The molecular mass of glucose (C_6 H_(12) O_6) molecule is

    A
    24 u
    B
    96 u
    C
    180 u
    D
    None of these
  • A solution contains 25% water, 25% ethanol ( C_(2)H_(5)OH ) and 50% acetic acid ( CH_(3)COOH ) by mass. The mole fraction of

    A
    water =0.502
    B
    ethanol = 0.302
    C
    acetic acid = 0.196
    D
    ethanol + acetic acid = 0.497
  • The molecular mass of glucose (C_(6) H_(12) O_(6)) molecule to three significant figures is

    A
    `180.162 u`
    B
    `180.0u`
    C
    `180.00u`
    D
    `1.80xx10^(2) u`
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