If 500 ml of 1 M solution of glucose is mixed with 500ml of 1M solution of glucose final moalrity of solution will be:

Options

A. 1M
B. 0.5M
C. 2M
D. 1.5M

Answer

To find the final molarity of the solution when 500 mL of 1 M glucose solution is mixed with another 500 mL of 1 M glucose solution, we can follow these steps:

### Step 1: Calculate the number of moles of glucose in each solution
- **Molarity (M)** is defined as moles of solute per liter of solution.
- For the first solution:
\[ \text{Moles of glucose} = \text{Molarity} \times \text{Volume (in L)} = 1 \, \text{M} \times 0.5 \, \text{L} = 0.5 \, \text{moles} \]
- For the second solution (which is identical):
\[ \text{Moles of glucose} = 1 \, \text{M} \times 0.5 \, \text{L} = 0.5 \, \text{moles} \]

### Step 2: Calculate the total number of moles of glucose
- Total moles of glucose after mixing both solutions:
\[ \text{Total moles} = 0.5 \, \text{moles} + 0.5 \, \text{moles} = 1 \, \text{mole} \]

### Step 3: Calculate the total volume of the mixed solution
- Total volume after mixing:
\[ \text{Total volume} = 500 \, \text{mL} + 500 \, \text{mL} = 1000 \, \text{mL} = 1 \, \text{L} \]

### Step 4: Calculate the final molarity of the mixed solution
- Final molarity (M) is calculated using the formula:
\[ \text{Molarity} = \frac{\text{Total moles}}{\text{Total volume (in L)}} \]
- Substituting the values:
\[ \text{Final molarity} = \frac{1 \, \text{mole}}{1 \, \text{L}} = 1 \, \text{M} \]

### Final Answer:
The final molarity of the solution after mixing is **1 M**.

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