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If above gaseous mixture at 273K is pass...

If above gaseous mixture at 273K is passed through KOH solution , contraction in volume (in litre) will be (assume KOH solution absorb `CO_(2)` gas completely):

A

11.2

B

22.4

C

44.8

D

89.6

Text Solution

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The correct Answer is:
B
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KOH is preferably used to absorb CO_(2) gas because :

N_2 is _____ in KOH solution while CO_2 is ____

Knowledge Check

  • A mixture of 100ml of CO,CO_(2) and O_(2) was sparked. When the resulting gaseous mixture was passed through KOH solution, contraction in volume was found to be 80ml , the composition of initial mixture may be (in the same order)

    A
    `30ml, 60ml, 10ml`
    B
    `30ml, 50ml, 20ml`
    C
    `30ml, 60ml, 20ml`
    D
    `30ml, 40ml, 30ml`

  • 12 mol gaseous mixture of an alkane and an alkene (containing same number of carbon atoms) require exactly 285 ml of air (containing 20% v/v O_(2) and rest N_(2) ) for complete combustion at 200K . After combustion when gaseous mixture is passes through KOH solution it shows volume contraction of 36 ml. Mole fraction of CO_(2) in final gaseous sample:

    A
    `(6)/(51)`
    B
    `(6)/(44)`
    C
    `(6)/(45)`
    D
    `(6)/(13)`

  • 12 mol gaseous mixture of an alkane and an alkene (containing same number of carbon atoms) require exactly 285 ml of air (containing 20% v/v O_(2) and rest N_(2) ) for complete combustion at 200K . After combustion when gaseous mixture is passes through KOH solution it shows volume contraction of 36 ml. Calculate mol % of oxygen which is converted into H_(2)O

    A
    0.3684
    B
    0.7368
    C
    0.2061
    D
    0.2563

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