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Outer electronic configuration of 4 elem...

Outer electronic configuration of 4 elements are as given below follows:
(1) `3d^(0)4s^(1)`
92) `3s^(2)3p^(5)`

Text Solution

Verified by Experts

(1) this element `(3d^(0)4s^(1))` is an s-block elemnt. So it is an element of 4th period is group 1.
(2) this element `(3s^(2)3p^(5))` is a p-block elements containing (2+5) or 7 electrons in the valency shell (n=3). So it is an element of the 3rd period in group (10+2+15)17.
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Knowledge Check

  • If the electronic configuration of an element is 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(2)4s^(2) , the four electrons involved in chemical bond formation will be:

    A
    `3p^6`
    B
    `3p^6, 4s^2`
    C
    `3p^6, 3d^2`
    D
    `3d^2, 4s^2`

  • What does the electronic configuration 1s^2 , 2s^2 , 2p^5 , 3s^1 indicate?

    A
    Ground state of fluorine
    B
    Excited state of fluroine
    C
    Excited state of neon
    D
    Excited state of the `O^(2-)` ions

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