Outer electronic configuration of 4 elements are as given below follows:
(1) `3d^(0)4s^(1)`
92) `3s^(2)3p^(5)`

Explanation

(1) this element `(3d^(0)4s^(1))` is an s-block elemnt. So it is an element of 4th period is group 1.
(2) this element `(3s^(2)3p^(5))` is a p-block elements containing (2+5) or 7 electrons in the valency shell (n=3). So it is an element of the 3rd period in group (10+2+15)17.