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The increasing order of the ionic radii ...

The increasing order of the ionic radii of the given isoelectronic species is-

A

`S^(2-),Cl^(2-),Ca^(2+),K^(+)`

B

`Ca^(2+),K^(+),Cl^(-),S^(2-)`

C

`K^(+),S^(2-),Ca^(2+),Cl^(-)`

D

`Cl^(-),Ca^(2+),K^(+),S^(2-)`.

Text Solution

Verified by Experts

The correct Answer is:
B
For any atom or ion, ionic radius `prop(e//Z)` [e=number of electrons and Z=atomic number]. Since the given ions are isoelectronic their electron number is also same. It means higher the atomic number lower will be the ionic radius of the ion. Therefore, the correct order of the ionic radii of the ions is `Ca^(2+) lt K^(+) lt Cl^(-) lt S^(2-)`.
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Knowledge Check

  • The group having isoelectronic species is-

    A
    `O^(2-), F^(-), Na^(+), Mg^(2+)`
    B
    `O^(-), F^(-), Na, Mg^(+)`
    C
    `O^(2-),F^(-),Na,Mg^(2+)`
    D
    `O^(-),F^(-),Na^(+),Mg^(2+)`.

  • The correct order of ionic radii is-

    A
    `N^(3-) gt O^(2-) gt F^(-) gt Na^(+)`
    B
    `N^(3-) gt Na^(+) gt O^(2-) gt F^(-)`
    C
    `Na^(+) gt O^(2-) gt N^(3-) gt F^(-)`
    D
    `O^(2-) gt F^(-) gt Na^(+) gt N^(3-)`

  • The correct increasing order of trans-effect of the following species is -

    A
    `CN^(-) gt Br^(-) gt C_(6)H_(5)^(-) NH_(3)`
    B
    `NH_(3) gt CN^(-) gt Br^(-) gt C_(6)H_(5)^(-)`
    C
    `CN^(-) gt C_(6)H_(5)^(-) gt Br^(-) gt NH_(3)`
    D
    `Br^(-) gt CN^(-) gt NH_(3) gt C_(6)H_(5)^(-)`

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    The correct order of the increasing ionic character is

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