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Maximum deviation from ideal gas is expe...

Maximum deviation from ideal gas is expected in case of-

A

`CH_(4)(g)`

B

`NH_(3)(g)`

C

`H_(2)(g)`

D

`N_(2)(g)`

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Knowledge Check

  • An ideal gas

    A
    can be liquefied if its temperature is more than critical temperature
    B
    can be liquefied if its pressure is more than critical pressure
    C
    cannot be liquefied at any pressure and temperature
    D
    can be liquefied ,if its temperature is more than Boyle’s temperature

  • For an ideal gas

    A
    the change in internal energy in a constant pressure process from temperature `The_1 to The_2` is equal to ``nC_v(T_2-T_1)` where `c_v` is the molar heat capacity at constant volume and n is the number of moles of the gas
    B
    the change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process
    C
    the internal energy does not change in an isothermal process
    D
    no heat is added or removed in an adiabatic process

  • The ideal gas equation is PV = nRT.Since none of the gas in universe is ideal one and deviation are noticed from ideal gas nature. The deviation from ideal gas nature has been explained in terms of compressibility factor= (Z=(PV)/(nNT)) Usually when Z > 1, repulsive force among molecules predominates When Z The gas which always shows predominative repulsive forces :

    A
    He
    B
    Ne
    C
    Ar
    D
    Kr