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Ligands are electron pair donor groups. ...

Ligands are electron pair donor groups. Ambidentate ligands are those ligands where two different atoms can donate electron pair. The complex where ambidentate ligands are present shows linkage isomerism.
Total number of linkage isomers that are present in `Na_(4)[Fe(CN)_(5)NOS]` is :

A

18

B

6

C

8

D

16

Text Solution

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The correct Answer is:
A
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Ambidentate ligands can show linkage isomerism .

Statement-1. Ambidentate ligands lead to linkage isomerism. Statement-2. The ionization sphere is different in different linkage isomers.

Knowledge Check

  • Ligands are electron pair donor groups. Ambidentate ligands are those ligands where two different atoms can donate electron pair. The complex where ambidentate ligands are present shows linkage isomerism. Total possible linkage isomers of K_(4)[Fe(CN)_(5)(NO_(2))] is :

    A
    12
    B
    10
    C
    6
    D
    4

  • Ligands are electron pair donor groups. Ambidentate ligands are those ligands where two different atoms can donate electron pair. The complex where ambidentate ligands are present shows linkage isomerism. The correct name of linkage isomer of [Co(NH_(3))_(5)(SCN)]SO_(4)

    A
    Pentaamminethiocyanato-S-cobalt (III) sulphate
    B
    Pentaamminethiocyanato-N-Cobalt (II) sulphate
    C
    Pentaamminethiocyanato-N-Cobalt (III) sulphate
    D
    Pentaamminecyanato-N-Cobalt (III) sulphate

  • Ligands are electron pair donor groups. Ambidentate ligands are those ligands where two different atoms can donate electron pair. The complex where ambidentate ligands are present shows linkage isomerism. The correct name of linkage isomer of [Co(NH_(3))_(5)(SCN)]SO_(4)

    A
    Pentaamminethiocyanato-S-cobalt (III) sulphate
    B
    Pentaamminethiocyanato-N-Cobalt (II) sulphate
    C
    Pentaamminethiocyanato-N-Cobalt (III) sulphate
    D
    Pentaamminecyanato-N-Cobalt (III) sulphate

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    A metal ion continues to accept electron pairs from the ligands till the total number of electrons present around the metal ion in the complex becomes becomes equal to the atomic number of

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