Home
Class 12
PHYSICS
A rod length L and mass M is placed alon...

A rod length `L` and mass `M` is placed along the `x`-axis with one end at the origin, as shown in the figure above. The rod has linear mass density `lamda=(2M)/(L^(2))x,` where `x` is the distance from the origin. Which of the following gives the `x`-coordinate of the rod's center of mass?

A

`2/3L`

B

`1/4L`

C

`1/3L`

D

`1/2L`

Text Solution

Verified by Experts

The correct Answer is:
A

`X_(cm)=1/M int x dm=1/M int_(0)^(L) x((2m)/(L^(2))x)dx=(2L)/3`
Promotional Banner

Similar Questions

Explore conceptually related problems

Find centre of mass of given rod of linear mass density lambda=(a+b(x/l)^2) , x is distance from one of its end. Length of the rod is l .

A non–uniform thin rod of length L is placed along x-axis as such its one of ends at the origin. The linear mass density of rod is lambda=lambda_(0)x . The distance of centre of mass of rod from the origin is :

The linear density of a thin rod of length 1m lies as lambda = (1+2x) , where x is the distance from its one end. Find the distance of its center of mass from this end.

Find coordinates of mass center of a non-uniform rod of length L whose linear mass density lambda varies as lambda=a+bx, where x is the distance from the lighter end.

A non uniform rod OM (of length l m) is kept along x-axis and rotating about an axis AB, which is perpendicular to rod as shown in the figure. The rod has linear mass densty that varies with the distance x from left end of the rod according to lamda=lamda_(0)((x^(3))/(L^(3))) Where unit of lamda_(0) is kg/m. What is the value of x so that moment of inertia of rod about axis AB (I_(AB)) is minimum?

A rod of length L is placed along the x-axis between x=0 and x=L. The linear mass density is lambda such that lambda=a+bx . Find the mass of the rod.

A rod of length l is placed along x - axis. One of its ends is at the origin. The rod has a non - uniform charge density lambda=(a)/(x) , a being a positive constant. The electric potential at the point P (origin) as shown in the figure is

A rod of length L and mass M_(0) is bent to form a semicircular ring as shown. The M.I. about X'X is

A rod of length L is placed along the x-axis between x = 0 and x = L. The linear density (mass/ length) lambda of the rod varies with the distance x from the origin as lambda = Rx . Here, R is a positive constant. Find the position of centre of mass of this rod.

A non-uniform thin rod of length L is palced along X-axis so that one of its ends is at the origin. The linear mass density of rod is lambda = lambda_(0)x . The centre of mass of rod divides the length of the rod in the ratio: