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Show that 3^nxx4^m cannot end with the d...

Show that `3^nxx4^m` cannot end with the digit 0 or 5 for any natural numbers 'n' and 'm'.

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Knowledge Check

  • The number of odd numbers lying between 40000 and 70000 that can be made from the digits 0, 1, 2, 4, 5, 7 if digits can be repeated any number of times is

    A
    1125
    B
    1296
    C
    766
    D
    655
  • The maximum number of electrons that can have the set of quantum numbers, n=4, m_(l)=0 and m_(s)=1/2 is

    A
    3
    B
    4
    C
    5
    D
    6
  • I. The number of all ten digited numbers that can be formed with all the distinct digits and which ar divisble by 4 is 15 times 81 . II. The number of positive integers that can be formed by using the digits 0, 1, 2, 3, 4, 5 without any repetition is 630.

    A
    Only I is true
    B
    Only II is true
    C
    Both I and II are true
    D
    Both I and II are false
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