Home
Class 12
PHYSICS
A charge moves in a circle perpendicular...

A charge moves in a circle perpendicular to a magnetic field. The time period of revolution is independent of

A

Magnetic fieldMagnetic field

B

Charge

C

Mass of the particle

D

Velocity of the particle

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    ERRORLESS |Exercise QUESTIONS|126 Videos

  • MAGNETISM

    ERRORLESS |Exercise Assertion & Reason|1 Videos

Similar Questions

Explore conceptually related problems

When a charged particle moves perpendicular to a magnetic field, then

A charge q, moving with velocity upsilon , enters a uniform magnetic field. The charge keeps on revolving along a closed circular path in the magnetic field. The frequency of revolution does not depend upon

Knowledge Check

  • When a charged particle moves perpendicular to a magnetic field, then:

    A
    speed of the particles is changed
    B
    speed of the particle remains unchanged
    C
    direction of motion of the particle remains unchanged
    D
    acceleration of the particle remains unchanged

  • If a charged particle is a plane perpendicular to a uniform magnetic field with a time period T Then

    A
    `T^(2)propr^(3)`
    B
    `T^(2)propr`
    C
    `Tpropr^(2)`
    D
    `Tpropr^(0)`

  • A charge particle is moving in a plane perpendicular to uniform magnetic field, then

    A
    Its momentum changes but kinetic energy remains the same
    B
    Both momentum and kinetic energy remain the same
    C
    Both will change
    D
    Kinetic energy change but momentum remains the same

    • Similar Questions

    Explore conceptually related problems

    What is the force acting on charge (q) moving in a direction perpendicular to a magnetic field (B) with velocity v?

    If a proton enters perpendicularly a magnetic field with velocity v, then time period of revolution is T. If proton enters with velocity 2v, then time period will be

    A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B . The time takeen by the particle to complete one revolution is

    Orbits of a particle moving in a circle are such that the perimeter of the orbit equals an integer number of de-Broglie wavelengths of the particle. For a charged particle moving in a plane perpendicular to a magnetic field, the radius of the n^(th) orbital will therefore be proportional to:

    A charge q , and mass m , is fired perpendicular to a magnetic field (B) with a velocity v . The frequency of revolution of the charge is

    Home
    Profile