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Explain reversible and irreversible proc...

Explain reversible and irreversible processes . Describe the working of Carnot engine . Obtain an expression for the efficiency .

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Reversible process : In reversible process a thermodynamic system can be retraced back in opposite direction to the changes that take place in the direct process or in forward process .
A reversible process is only an ideal concept .
Examples for reversible process :
1) Peltier effect and Seebeck effect .
2) Fusion of ice and vapourisation of water .
Irreversible process : A thermodynamic process that cannot be taken back in oposite direction is called "irreversible process."
Examples :
1) Work done against frition
2) Magnetization of materials .
Carnot's Engine : Carnot's engine works on the principle of reversible process with-in the temperatures `T_(1) and T_(2)`
It consists of four continuous processes .
Total process is known as Carnot Cycle .
Step 1 : In carnot cycle the 1st step consists of isothermal expansion of gases . So temperature T is constant , P ,V changes are shown as`P_(1)V_(1)T_(1)overset("to")rarrP_(2)V_(2)T_(2)`
Work done in isothermal process
`W_(1rarr2)=Q_(1)-muRT_(1)log_(e)((V_(2))/(V_(1)))" " ....(1)`
Step : 2 In this stage gases will expand adiabatically . So energy to the system Q is constant .
So , P,V relation is `P_(2)V_(2)T_(1)overset("to")rarrP_(3)V_(3)T_(2)`
Work done in adiabatically process
`W_(2rarr3)=(muR(T_(1)-T_(2)))/(gamma-1)" " ...(2)`

Step 3 : In this stage gases will be compressed isothermally , So `P_(1)V` changes are `P_(3)V_(3)T_(2)overset("to")rarrP_(4)V_(4)T_(2)`
Work done in isothermal compression
`W_(3rarr4)=Q_(1)-muRTlog_(e)((V_(3))/(V_(4)))" " ....(3)`
Step 4 : In the fourth stage the gas suffers adiabatic compression and returns to original stage .
So , P,V changes are `P_(4)V_(4)T_(2)overset("to")rarrP_(1)V_(1)T_(1)`
Work done `W_(4rarr1)=(muR(T_(2)-T_(1))/(gamma-1)" " ...(4)`
Total work done `W=muRT_(1)log((V_(2))/(V_(1)))`
`+(muR)/(gamma-1)(T_(1)-T_(2))-muRT_(2)log(V_(3)/(V_(4)))-(muR)/(gamma-1)(T_(1)-T_(2))`
`therefore W=muRT_(1)log((V_(2))/(V_(1)))-muRT_(2)log(V_(3)/(V_(4)))`
The total work done `W=Q_(1)-Q_(2)` i.e., the difference to heat energy absorbed from source and heat energy given to sink Efficiency of Carnot engine
`eta=("work done by Carnot engine")/("heat energy supplied")`
`thereforeeta=(Q_(1)-Q_(2))/(Q_(1))" or " eta=1-(Q_(2))/(Q_(1))=1-(T_(2))/(T_(1))`
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Knowledge Check

  • A carnot has the reversible processes the following order

    A
    Isothermal expansion, adiabatic expansion, isothermal compression and adiabatic compression
    B
    Isothermal compression, adiabatic compression, Isothermal expansion, adiabatic expansion,
    C
    Adiabatic expansion, Isothermal expansion, isothermal compression and adiabatic compression
    D
    Adiabatic expansion, Isothermal expansion,adiabatic compression, isothermal compression
  • Even Carnot engine cannot give 100% efficiency because we cannot

    A
    prevent radiation
    B
    find ideal sources
    C
    reach absolute zero temperature
    D
    eliminate friction
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