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Equal volume of 1.0 M KCl and 1.0 M AgNO...

Equal volume of `1.0` M KCl and `1.0 M AgNO_(3)` are mixed . The depression of freezing point of the resulting solution will be :
(`K_(f) (H_(2)O) = 1.86K kg mol^(-1)` , Assume : 1M = 1m)

A

`3.72 K `

B

`1.86K`

C

`0.93K`

D

None of these

Text Solution

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The correct Answer is:
B
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Calculate depression of freezing point for 0.56 molal aq. Solution of KCl. (Given : K_f(H_(2)O) = 1.8 kg mol^(-1) ).

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Knowledge Check

  • 0.1 M KI and 0.2 M AgNO_(3) are mixed in 3 : 1 volume ratio. The depression of freezing point of the resulting solution will be [ K_(b)(H_(2)O) = 1.86 K kg "mol"^(-1) ]:

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    3.72 K
    B
    1.86 K
    C
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    D
    0.279 K

  • Calculate depression of freezing point for 0.56 molal aq. Solution of KCl. (Given : K_(f(H_(2)O)) = 1.8 K kg mol^(-1)) .

    A
    2
    B
    3
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    4
    D
    5

  • 0.05 m urea solution will have freezing point ( K_(f) = 1.86 K kg "mol"^(-1) )

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    30 mL of 0.1M KI_(aq.) and 10 mL of 0.2M AgNO_(3) are mixed. The solution is then filtered out. Assuming that no change in total volume, the resulting solution will freezing at: [K_(f) "for" H_(2)O = 1.86K kg mol^(-1) , assume molality = molality]

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