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The freezing pont depression of a -0...

The freezing pont depression of a `-0.2046^(@)`C . What is the equlibrium constant for the reaction at 298 K ?
`HCOO^(-)(aq) + H_(2) O(l)iffHCOOH(aq) + OH^(-) (aq)`
`(Given : K_(f) (H_(2)O)=1.86 K kg mol^(-)`, " Molartiy = molality")

A

`1.1xx10^(-3)`

B

`9xx10^(-12)`

C

`9xx10^(-13)`

D

`1.1xx10^(-11)`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The equilibrium constant expression for the reaction , HPO_4^(2-)(aq) + H_(2)O(l) iff H_3O^(+)(aq) + PO_4^(3-)(aq) is -

    A
    `K_(C) = ([H_3O^(+) (aq)][PO_4^(3-)(aq)])/([HPO_4^(2-)(aq)])`
    B
    `K_(C) = ([H_3O^(+)(aq) ][PO_4^(3-)(aq)])/([H_2O(l)])`
    C
    `K_(C) = ([HPO_4^(2-)(aq)][H_2O(l)])/([H_3O(+)(aq)][PO_4^(3-)(aq)])`
    D
    None of these

  • The freezing point depression of a 0.1 M aq. Solution of weak acid (HX) is -0.20^(@)"C". What is the value of equilibrium constant for the reaction: "HX(aq)"iff"H"^(+)"(aq)"+"X"^(-1)"(aq)" [Given: "K"_("f")" for water=1.8 Kg mol"^(-1)"K. & Molality=Molarity" ]

    A
    `1.46xx10^(-4)`
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    D
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  • The equilibrium constant for the reaction given is 3.6xx10^(-7)OCl^(-)(aq)+H_2O(l)hArrHOCl(aq)+OH^(-)(aq). What is Ka for HOCl ?

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