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Four cells each of emf E are internal re...

Four cells each of emf E are internal resistance r, are connected In series across an external resistance R. By mistake one of the cells is connected in reverse. Then the current in the external circuit is

A

`(2E)/(4r+R)`

B

`(3E)/(4r+R)`

C

`(3E)/(3r+R)`

D

`(2E)/(3r+R)`

Text Solution

Verified by Experts

The correct Answer is:
A
Current in the circuit `I=(3E-E)/(4r+R)=(2E)/(4r+R)`
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