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One requires 11 eV of energy to dissocia...

One requires 11 eV of energy to dissociate a carbon monoxide molecule into carbon and oxygen atoms. The minimum frequency of the appropriate electromagnetic radiation to achieve the dissociation lies in

A

visible region

B

infrared region

C

ultraviolet region

D

microwave region

Text Solution

Verified by Experts

`E=hf` and `c=flambda`
`therefore lambda=(hc)/E`
`=(6.63xx10^(-34)xx3xx10^8)/(11xx1.6xx10^(-19))=1.13xx10^(-7)` m
`therefore ` The wave lies in the ultraviolet region.
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Knowledge Check

  • H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . Which among the following differences in the energy levels for a Li^(2+) ion is minimum ?

    A
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    B
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    C
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    D
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    A
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    B
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    C
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    D
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    A
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