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The gas equation for n moles of a real g...

The gas equation for n moles of a real gas is `(P+(a)/(V^(2)))(V-b) = nRT` where P is the pressure, V is the volume, T is the absolute temperature, R is the molar gas constant and a, b are arbitrary constants. Which of the following have the same dimensions as those of PV ?

A

nRT

B

`a//V`

C

Pb

D

`ab//V^(2)`

Text Solution

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The correct Answer is:
To solve the question, we need to analyze the given gas equation and determine which expressions have the same dimensions as \( PV \). ### Step-by-Step Solution: 1. **Understanding the Gas Equation**: The gas equation given is: \[ (P + \frac{a}{V^2})(V - b) = nRT \] Here, \( P \) is pressure, \( V \) is volume, \( T \) is absolute temperature, \( R \) is the molar gas constant, and \( a \) and \( b \) are constants. 2. **Identifying Dimensions**: - The dimension of pressure \( [P] \) is given by: \[ [P] = \frac{M}{L \cdot T^2} \] - The dimension of volume \( [V] \) is: \[ [V] = L^3 \] - The dimension of the gas constant \( R \) is: \[ [R] = \frac{M}{L \cdot T^2 \cdot N} \] - The dimension of \( n \) (number of moles) is: \[ [n] = N \] - The dimension of temperature \( [T] \) is: \[ [T] = \Theta \] 3. **Finding Dimensions of \( nRT \)**: The dimensions of \( nRT \) can be calculated as follows: \[ [nRT] = [n] \cdot [R] \cdot [T] = N \cdot \frac{M}{L \cdot T^2 \cdot N} \cdot \Theta = \frac{M \cdot \Theta}{L \cdot T^2} \] 4. **Finding Dimensions of \( PV \)**: The dimensions of \( PV \) are: \[ [PV] = [P] \cdot [V] = \left(\frac{M}{L \cdot T^2}\right) \cdot (L^3) = \frac{M \cdot L^2}{T^2} \] 5. **Equating Dimensions**: From the equation \( (P + \frac{a}{V^2})(V - b) = nRT \), we can see that the left-hand side must have the same dimensions as the right-hand side. Thus, we can conclude: \[ \text{Dimensions of } (P + \frac{a}{V^2})(V - b) = \frac{M \cdot L^2}{T^2} \] 6. **Analyzing Each Option**: - **Option A**: \( nRT \) has dimensions \( \frac{M \cdot L^2}{T^2} \) (Correct). - **Option B**: \( \frac{a}{V^2} \) must also have dimensions of pressure, thus when multiplied by \( V \) gives \( PV \) (Correct). - **Option C**: \( P \cdot (V - b) \) also results in \( PV \) (Correct). - **Option D**: \( \frac{a}{V^2} \cdot V \cdot b \) gives \( PV \) (Correct). ### Conclusion: All four options have the same dimensions as \( PV \).
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