Home
Class 11
CHEMISTRY
What amount of ice (in g) will remain wh...

What amount of ice (in g) will remain when 52 g ice is added to 100 g of water at `40^(@)C`? Specific hate of water is 1 cal//g and latent heat of fusion of ice is `80 cal//g` Round off your answer to next interger.

Text Solution

Verified by Experts

The correct Answer is:
19
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SALT ANALYSIS

    GRB PUBLICATION|Exercise Subjective Type|69 Videos

Similar Questions

Explore conceptually related problems

What amount of ice will remains when 52 g ice is added to 100 g of water at 40^(@)C ? Specific heat of water is 1 cal/g and latent heat of fusion of ice is 80 cal/g.

What does the statement, 'latent heat of fusion for ice is 80 cal/g' mean?

Knowledge Check

  • What will be the final temperature when 150 g of ice at 0^@C is mixed with 300 g of water at 50^@C . Specific heat of water =1 cal//g//^@C . Latent heat of fusion of ice =80 cal//g .

    A
    `7.6^@C`
    B
    `6.7^@C`
    C
    `5.8^@C`
    D
    `8.5^@C`

  • 50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)

    A
    `0^@C`
    B
    `40^@C`
    C
    `60^@C`
    D
    less than `0^@C`

  • 1 g of ice at 0^(@) C is added to 5 g of water at 10^(@) C. If the latent heat is 80 cal/g, the final temperature of the mixture is

    A
    `5^(@)` C
    B
    `0^(@)`C
    C
    `-5^(@)`C
    D
    None of these

    • Similar Questions

    Explore conceptually related problems

    What does the statement, 'latent heat of fusion for ice is 80 cal/g' mean?

    Find the heat required to convert 20 g of iceat 0^(@)C into water at the same temperature. ( Specific latent heat of fusion of ice =80 cal//g )

    Specific latent of fusion of ice is 80 cal/g. Explain this statement ?

    How many calories of heat will be absorbed when 2kg of ice at 0^(@)C melts ? ( Specific latent heat of fusion of ice = 80 cal //g )

    100 g of ice at 0^(@) C is mixed with 100 g of water at 80^(@) C. The resulting temperature is 6^(@) C. Calculate heat of fusion of ice.

    Home
    Profile