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The equation of the circle passing throu...

The equation of the circle passing through (1,5) and (4,1) and touching y-axis is ` x^(2) + y^(2) -5x -6y + 9 + lamda (4x + 3y-19) = 0` where ` lamda ` is equal to

A

`0 , - 40/9`

B

0

C

`40/9`

D

`(-40)/9`

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The correct Answer is:
A
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Knowledge Check

  • The equation of the circle passing through (1,5) and (4,1) and touching y-ais is x ^(2) + y ^(2) - 5x - 6y + 9 + lamda ( 4x + 3y -19) = 0 where lamda is equal to

    A
    `0, - (40)/(9)`
    B
    `0`
    C
    `(40)/(9)`
    D
    `(-40)/(9)`

  • The equation of the plane passing through (1,2,3) and parallel to 3x-2y+4z=5 is

    A
    3x-2y+4z=11
    B
    3x-2y+4z=0
    C
    3x-2y+4z=10
    D
    3(x-1)-2(y-2)+4(z-3)=5

  • The equation of the plane passing through (2,3,4) and parallel to the plane 5x-6y+7z=3 is

    A
    5x-6y+7z+20=0
    B
    5x-6y+7z-20=0
    C
    `-5x+6y-7z+3=0`
    D
    `5x+6y+7z+3=0`

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