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The escape velocity for a planet is v(e)...

The escape velocity for a planet is `v_(e)`. A particle is projected from its surface with a speed `v`. For this particle to move as a satellite around the planet,

A

`(v_(e))/(2) lt v lt v_(e)`

B

`(v_(e))/(sqrt(2)) lt v lt v_(e)`

C

`v_(e) lt v lt sqrt()2v_(e)`

D

`(v)/(sqrt()2) lt v lt (v_(e))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • The escape velocity of an object projected from the surface of a given planet is independent of

    A
    mass of the planet
    B
    the mass of the object
    C
    the radius of the planet
    D
    the direction of projection
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    `v_(e)`
    B
    `1.5 v_(e)`
    C
    `sqrt(1.5) v_(e)`
    D
    `2 v_(e)`
  • The escape velocity for a body projected from a planet depends on

    A
    mass of the body
    B
    angle of projection
    C
    mass of the planet
    D
    radius of the body
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