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The temperatuer coefficient, of the emf,...

The temperatuer coefficient, of the emf, i.e., `(dE)/(dt) = -0.00065` Volt `deg^(-)` for the cell, `Cd| CdCl_(2)(1 M) ||AgCl(s)| Ag` at `25^(@)`.
Calcualte the entropy changes `DeltaS_(298K)` for the cell reaction,
`Cd + 2AgCl rightarrow Cd^(2+) + 2Cl^(-) + 2Ag`

A

`-105.5JK^(-)`

B

`-150.2 JK^(-)`

C

`-75.7 JK^(-)`

D

`-125.5 JK^(-)`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • The temperature coefficient of the emf i.e. (dE)/(dT)=0.00065"volt".deg^(-1) for the cell Cd|CdCl_(2)(1M)||AgCl(s) |Ag at 25^(@)C calculate the entropy changes triangleS_(298K) for the cell reaction, Cd+2AgCltoCd^(++)+2Cl^(-)+2Ag

    A
    `-105.5JK^(-1)`
    B
    `-150.2JK^(-1)`
    C
    `-75.7JK^(-1)`
    D
    `-125.5JK^(-1)`

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    A
    `-1.207` V
    B
    `+1.207` V
    C
    `-0.391 V `
    D
    `+0.391 V `

  • The emf of the following cell: Cd(s)| CdCl_(2) (0.10M)|AgCl(s)Ag(S) Is 0.6915V at 0.6753V at 25^(@) C . The DeltaH of reaction in KJ at 25^(@)C is

    A
    (-176)
    B
    (-234.7)
    C
    `(123.5)`
    D
    `(-167.6)`
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