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For a saturated solution of AgCl at 25^(...

For a saturated solution of AgCl at `25^(@)C,k=3.4xx10^(-6) ohm^(-1)cm^(-1)` and that of `H_(2)O` (l) used is `2.02xx10^(-6) ohm^(-1) cm^(-1),lambda_(m)^(@)` for AgCl is 138 `ohm^(-1) cm^(2) "mol"^(-1)` then the solubility of AgCl in "mole"s per litre will be:

A

`10^(-5)`

B

`10^(-10)`

C

`10^(-14)`

D

`10^(-16)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • For a saturated solution of AgCl at 25^(@)C,k=3.4xx10^(-6)ohm^(-1)cm^(-1) and that of H_(2)O(l) used is 2.02xx10^(-6)ohm^(-1)cm^(-1). lambda_(m)^(@) for AgCl is 138ohm^(-1)cm^(2)mol^(-1) then the solubility of AgCl in moles per liter will be

    A
    `10^(-5)`
    B
    `10^(-10)`
    C
    `10^(-14)`
    D
    `10^(-16)`

  • The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solubility of AgC at 25^(@)C is:

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    `2.6xx10^(-5)M`
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  • The specific conducitvity of a saturated solution of AgCI is 3.40 xx 10^6 "ohm"^(-1) cm^(-1) at 25^@C . If lambda_(Ag+) = 62.3 "ohm"^(-1) cm^2 "mol"^(-1) and lambda_(CI-) = 67.7 "ohm"^(-1) cm^2 "mol"^(-1) , the solubility of AgCI at 25^@C is.

    A
    ` 2.6 xx 10^(-5) "mol" L-1`
    B
    ` 3.731 xx 10^(-3) "mol" L-1`
    C
    ` 3.731 xx10^(-5) "mol" L-1`
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    ` 2.6 xx 10^(-3) g L-1`

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