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At 0.04 M concentration, the molar condu...

At 0.04 M concentration, the molar conductivity of solution of an electrolyte is `5000 Omega^(-1)cm^(2) mol^(-1)` while at 0.01 M concentration the value is `5100 Omega^(-1)cm^(2)mol^(-1)`. Making necessary assumption (Taking it as strong electrolyte) find the molar conductivity at infinite dilution and write percentage dissociation of strong electrolyte at 0.04 M.

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At 0.04 M concentration the molar conductivity of a solution of a electrolyte is 5000Omega^(-1)cm^(2)mol^(-1) while at 0.01 M concentration the value is 5100Omega^(-1)cm^(2)mol^(-1) making necessary assumption (taking it as strong electrolyte) find the molar conductivity at infinite dilution and also determine the degree of dissociation of strong electrolyte at 0.04M.

The molar conductivity of 0.05 M BaCI_(2) solution at 25^(@)C is 223 Omega^(-1) cm^(2) mol^(-1) .What is its conductivity ?

Knowledge Check

  • The molar conductivity of a 1.5 M solution of an electrolyte is found to be 138.9 S cm^(2) mol^(-1) . Calculate the conductivity of the solution.

    A
    `1.023 S cm^(-1)`
    B
    `0.026 S cm^(-1)`
    C
    `0.208 S cm^(-1)`
    D
    `0.325 S cm^(-1)`

  • The molar conductivity of 0.05 M solution of weak acid is 16.6Omega^(-1)cm^(-2)mol^(-1). Its molar conductivity at infinite dilution is 390.7Omega^(-1)cm^(-2)mol^(-1) . The degree of dissociation of weak acid is

    A
    0.24
    B
    0.42
    C
    0.042
    D
    0.024

  • Molar conductivity of a solutions is 1.26xx10^(2) Omega^(-1)cm^(2) "mol"^(-1) its molarity is 0.01. its specific conductivity will be

    A
    `1.26xx10^(-25)`
    B
    `1.26xx10^(-3)`
    C
    `1.26xx10^(-4)`
    D
    `0.0063`

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    The molar conductivity of 0.05 M BaCl_(2) solution at 25^(@)C is 223 Omega^(-1)"cm"^(2) mol^(-1) . What is its conductivity?

    The molar conductivity of 0.05 M BaCl_(2) solution at 25^(@)C is 223Omega^(-1)cm^(2)mol^(-1) . What is its conductivity?

    The molar conductivity of a 1.5 M solution of an electrolyte is found to be 138.9 S cm^(2) mol^(-1) . Calculate the conductivity of this solution.

    Molar conductivity of a 1.5 m solustion of an electrolyte is found to be 138.9 S cm^(2) mol^(-1) . Calculate the conductivity of this solution.

    The molar conductivity of 0.05 M of solution of an electrolyte is 200 Omega^(-1) cm^2 . The resistance offered by a conductivity cell with cell constant (1//3) cm^(-1) would be about .

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