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A conducting loop rotates with constant ...

A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field, whose direction is perpendicular to that fixed diameter.

A

The emf will be maximum at the movement when flux is zero.

B

The emf will be '0' at the moment when flux is maximum.

C

The emf will be maximum at the moment when plane of the loop is parallel to the magnetic field

D

The phase difference between the flux and the emf is `pi//2`

Text Solution

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The correct Answer is:
A, B, D
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Knowledge Check

  • When a 'J' shaped conducting rod rotating in its own plane with constant angular velocity omega, avout one of its end P, in a uniform magnetic field vec(B) directed normally into the plane of paper) then magnetic of emf induced across it will be

    A
    `Bomegasqrt(L^(2)+l^(2))`
    B
    `1/2 BomegaL^(2)`
    C
    `1/Bomega(L^(2)+l^(2))`
    D
    `1/2Bomegal^(2)`

  • When a 'j' shaped conducting rod is rotating in its own plane with constant angular velocity omega about one of its ends P in a uniform magnetic field rarr B ( directed normally into the plane of paper ) the magnitude of emf induced across it will be

    A
    `B omega sqrt(L^(2)+l^(2))`
    B
    `(1)/(2) B omegal L^(2)`
    C
    `(1)/(2) B omega (L^(2)+l^(2))`
    D
    `(1)/(2) B omegal^(2)`

  • A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is

    A
    `Bomegal^(2)`
    B
    `(1)/(2)Bomegal^(2)`
    C
    `(1)/(8)Bomegal^(2)`
    D
    zero

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