A particle moves with deceleration along a circle of radius R so that at any moment its tangential and normal accelerations are equal in moduli. At the initial moment `t=0` the velocity of the point equals `v_(0)`. Find (a) the velocity of the point as a function of t and s , (b) the resultant acceleration modulus as a function of `v`.

A point moves with decleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t=0 the velocity of the point equals v_0 . Find: (a) the velocity of the point as a function of time and as a function of the distance covered s_1 , (b) the total acceleration of the point as a function of velocity and the distance covered.

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals v_(0) , then th speed of the particle as a function of the distance covered S will be

A particle moves with decreasing speed along the circle of radius R so that at any moment of time its tangential and centripetal accelerations are equal in magnitude. At the initial moment , t =0 its speed is u. The magnitude of tangential acceleration at t = R/(2u) is

A particle moves with decreasing speed along the circle of radius R so that at any moment of time its tangential and centripetal accelerations are equal in magnitude. At the initial moment , t =0 its speed is u. The time after which the speed of particle reduces to half of its initial value is

A particle is moving on a circle of radius R such that at every instant the tangential and radial accelerations are equal in magnitude. If the velocity of the particle be v_(0) at t=0 , the time for the completion of the half of the first revolution will be

A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is

A particle is moving along a circular path ofradius R in such a way that at any instant magnitude of radial acceleration & tangential acceleration are equal. 1f at t = 0 velocity of particle is V_(0) . Find the speed of the particle after time t=(R )//(2V_(0))

A particle is moving in a circle of radius R in such a way that at any instant the normal and tangential components of the acceleration are equal. If its speed at t = 0 is u_(0) the time taken to complete the first revolution is :