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A simple pendulam swings with amplitude of 5 cm and time period 2 s. Calculate its maximum velocity, maximum acceleration and velocity when it is 2 cm away from its mean position.

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Knowledge Check

  • A particle is executing sin1ple harmonic motion with an amplitude of 2 m. The difference in the magnitude of its maximum acceleration and maximum velocity is 4. The time period of its oscillation and its velocity when it is l m away from the mean position are respectively

    A
    `2s,2sqrt3ms^(-1)`
    B
    `7/(22)s,4sqrt3" "ms^(-1)`
    C
    `(22)/7s,2sqrt3ms^(-1)`
    D
    `(44)/7s,4sqrt3ms^(-1)`

  • A particle executes a linear S.H.M. of amplitude 8 cm and period 2s. The magnitude of its maximum velocity is

    A
    `8pi` cm/second
    B
    `16 pi` cm/second
    C
    `4pi` cm/second
    D
    `2pi` cm/second

  • A simple pendulum of length 98cm has amplitude of 2sqrt10 cm. Taking g=9.8m//s^2 , its maximum velocity will be

    A
    2 cm/s
    B
    0.2 cm/s
    C
    10 cm/s
    D
    20 cm/s

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    A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2s . Find the acceleration and velocity of the body when the displacement is (a) 5cm, (b) 3cm, (c) 0 cm.

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