A ball is thrown straight up in air with...

A ball is thrown straight up in air with an initial velocity u. Air exerts a force on it in horizontal direction which produces an acceleration depending on its height from ground as `a_(x) = ah^(2)`. Find the displacement of ball from the projection point as a function of time.

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The correct Answer is:

[`r = sqrt(x_(t)^(2) + y_(t)^(2))` where `x_(t) = (au^(2)t^(4))/(12) + (ag^(2) t^(6))/(120) - (aug t^(5))/(20), y_(1) ut - (1)/(2) g t^(2)]`

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A ball is thrown straight up in the air. For which situation are both the instantaneous velocity and the acceleration zero ?

one the way up

at the top of its flight path

halfway up and halfway down

none of the above

`vsqrt((mg)/(mg+F))`

`vsqrt((F)/(mg+F))`

`vsqrt((mg-F)/(mg+F))`

None of these

`v sqrt((mg)/(mg+F))`

`v sqrt((F)/( mg +F))`

`v sqrt((mg -F)/( mg +F))`

`v sqrt((mg +F)/( mg ))`