Home
Class 11
PHYSICS
The wavelength lambda associated with a ...

The wavelength `lambda` associated with a moving electron depends on its mass m , its velocity v and Planck's constant h . Prove dimensionally that `lambda prop (h)/(mv)`.

Answer

Step by step text solution for The wavelength lambda associated with a moving electron depends on its mass m , its velocity v and Planck's constant h . Prove dimensionally that lambda prop (h)/(mv). by PHYSICS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • PHYSICAL WORLD AND MEASUREMENTS

    SL ARORA|Exercise Based on Significant|15 Videos

  • PHYSICAL WORLD AND MEASUREMENTS

    SL ARORA|Exercise Based on Errors in Measurements|3 Videos

  • PHYSICAL WORLD AND MEASUREMENTS

    SL ARORA|Exercise problem for self practice|64 Videos

  • Physical world

    SL ARORA|Exercise Exercise|49 Videos

  • PROJECTILE MOTION

    SL ARORA|Exercise Problem For Self Practice|50 Videos

Similar Questions

Explore conceptually related problems

What will happen to the wavelength associated with a moving particle if its velocity is doubled ?

What will happen to the wavelength associated with a moving particles if its velocity is reduced to half ?

Knowledge Check

  • The wavelength associated with a moving particle depends upon p^(th) power of its mass m, q^(th) power of its velocity v and power of plank's constant h Then the corrent set of valume of p,q and r is

    A
    `p= 1, q= -1, r = 1`
    B
    `p= 1, q= 1, r = 1`
    C
    `p= -1, q= -1, r = -1`
    D
    `p= -1, q= -1, r = 1`

  • The debroglie wavelength associated with a particle of mass m, moving with a velocity v and energy E isgiven by

    A
    `h//mv^(2)`
    B
    `mv//h^(2)`
    C
    `h//sqrt(2mE)`
    D
    `sqrt(2mE)//h`

  • The de - Broglie wavelength associated with the particle of mass m moving with velocity v is

    A
    `h//mv`
    B
    `mv//h`
    C
    `h//2v`
    D
    `m//hv`

    • Similar Questions

    Explore conceptually related problems

    According to de-Broglie hypothesis, the wavelength associated with moving electron of mass 'm' is 'lambda_(e)' . Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is 'lambda_(p)' . If the energy (E) of electron and photonm is same, then relation between lambda_e and 'lambda_(p)' is

    In 1924, de-Broglie proposed that every particle possesses wave properties with a wavelength , lambda given by lambda = h/(mv) where m is the mass of the particle, v is its velocity and h is Planck's constant. The de-Broglie prediction was confirmed experimentally when it was found that an electron beam undergoes diffraction , a phenomenon characteristic of waves. The de-Broglie wavelength can be estimated by measuring kinetic energy of an electron accelerating by a potential V as : 1/2 mv^2 = eV "where" 1eV = 1.6 xx 10^(-19) J, h = 6.6 xx 10^(-34) Js . The mass of a photon moving with velocity of light having wavelength same as that of an alpha - particle (mass = 6.6 xx 10^(-27)kg) moving with velocity of 2.5 xx 10^2 ms^(-1) is

    In 1924, de-Broglie proposed that every particle possesses wave properties with a wavelength , lambda given by lambda = h/(mv) where m is the mass of the particle, v is its velocity and h is Planck's constant. The de-Broglie prediction was confirmed experimentally when it was found that an electron beam undergoes diffraction , a phenomenon characteristic of waves. The de-Broglie wavelength can be estimated by measuring kinetic energy of an electron accelerating by a potential V as : 1/2 mv^2 = eV "where" 1eV = 1.6 xx 10^(-19) J, h = 6.6 xx 10^(-34) Js . The proton and He^(2+) are accelerated by the same potential, then their de-Broglie wavelengths lambda_(He^(2+)) and lambda_p are in the ratio of (m_(He^(2+)) = 4m_p) :

    In 1924, de-Broglie proposed that every particle possesses wave properties with a wavelength , lambda given by lambda = h/(mv) where m is the mass of the particle, v is its velocity and h is Planck's constant. The de-Broglie prediction was confirmed experimentally when it was found that an electron beam undergoes diffraction , a phenomenon characteristic of waves. The de-Broglie wavelength can be estimated by measuring kinetic energy of an electron accelerating by a potential V as : 1/2 mv^2 = eV "where" 1eV = 1.6 xx 10^(-19) J, h = 6.6 xx 10^(-34) Js . If lambda is the wavelength associated with the electron in the 4th circular orbit of hydrogen atom, then radius of the orbit is

    In 1924, de-Broglie proposed that every particle possesses wave properties with a wavelength , lambda given by lambda = h/(mv) where m is the mass of the particle, v is its velocity and h is Planck's constant. The de-Broglie prediction was confirmed experimentally when it was found that an electron beam undergoes diffraction , a phenomenon characteristic of waves. The de-Broglie wavelength can be estimated by measuring kinetic energy of an electron accelerating by a potential V as : 1/2 mv^2 = eV "where" 1eV = 1.6 xx 10^(-19) J, h = 6.6 xx 10^(-34) Js . The wavelength of matter wave associated with an electron passing through an electric potential of 100 million volts is

    Home
    Profile