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The radius of the earth is 6000 km . Wha...

The radius of the earth is 6000 km . What will be the weight of a 120 kg body if it is taken to a height of 2000 km above the surface of the earth?

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To find the weight of a 120 kg body at a height of 2000 km above the surface of the Earth, we can follow these steps: ### Step 1: Determine the total distance from the center of the Earth The radius of the Earth is given as 6000 km. When the body is taken to a height of 2000 km above the Earth's surface, the total distance from the center of the Earth (R + h) can be calculated as follows: \[ \text{Total distance} = \text{Radius of the Earth} + \text{Height above the surface} \] \[ \text{Total distance} = 6000 \text{ km} + 2000 \text{ km} = 8000 \text{ km} \] ### Step 2: Convert the distance into meters Since the standard unit of measurement in physics is meters, we need to convert kilometers to meters: \[ 8000 \text{ km} = 8000 \times 1000 \text{ m} = 8,000,000 \text{ m} \] ### Step 3: Use the formula for gravitational field intensity at height h The gravitational field intensity (g') at a height h above the Earth's surface can be calculated using the formula: \[ g' = \frac{G M}{(R + h)^2} \] Where: - \( G \) is the gravitational constant, approximately \( 6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \) - \( M \) is the mass of the Earth, approximately \( 5.972 \times 10^{24} \, \text{kg} \) - \( R \) is the radius of the Earth in meters, which is \( 6000 \, \text{km} = 6,000,000 \, \text{m} \) ### Step 4: Calculate the gravitational field intensity at the height Substituting the values into the formula: \[ g' = \frac{(6.674 \times 10^{-11}) \times (5.972 \times 10^{24})}{(8,000,000)^2} \] Calculating the denominator: \[ (8,000,000)^2 = 64 \times 10^{12} = 6.4 \times 10^{13} \, \text{m}^2 \] Now substituting back into the equation: \[ g' = \frac{(6.674 \times 10^{-11}) \times (5.972 \times 10^{24})}{6.4 \times 10^{13}} \] Calculating the numerator: \[ 6.674 \times 10^{-11} \times 5.972 \times 10^{24} \approx 3.986 \times 10^{14} \, \text{N m}^2/\text{kg} \] Now substituting this into the equation for \( g' \): \[ g' = \frac{3.986 \times 10^{14}}{6.4 \times 10^{13}} \approx 6.22 \, \text{m/s}^2 \] ### Step 5: Calculate the weight of the body at that height The weight (W) of the body can be calculated using the formula: \[ W = m \cdot g' \] Where \( m \) is the mass of the body (120 kg): \[ W = 120 \, \text{kg} \times 6.22 \, \text{m/s}^2 \approx 746.4 \, \text{N} \] ### Final Answer The weight of the 120 kg body at a height of 2000 km above the surface of the Earth is approximately **746.4 N**. ---
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