1000 ml 2 M CuSO_(2) is electolyses by a current of 9.65 amp for 2 hour which is //are correct?
When CuSO_(4) is electrolysed, using Pt electrodes
100L aqueous solution of KBr is electrlysed by using current of 9.65 ampere for 10 seconds, using Pt electrode. Which of the following species will not be produced due to electrolysis?
100L aqueous solution of KBr is electrlysed by using current of 9.65 ampere for 10 seconds, using Pt electrode. pH of the the resulting solution in cell will be:
A test for complete removal of Cu^(2+) ions from a solution of Cu^(2+) (aq) is to add NH_3 (aq). A blue colour signifies the formation of complex [Cu(NH_3)_4]^(2+) having K_f = 1.1 xx 10^13 and thus confirms the presence of Cu^(2+) in solution. 250 mL of 0.1 M CuSO_4 (aq.) is electrolysed by passing a current of 3.512 ampere for 1368 second. After passage of this charge sufficient quantity of NH_3 (aq) is added to electrolysed solution maintianing [NH_3] = 0.10 M. If [Cu(NH_3)_4]^(2+) is detectable upto its concentration as low as 1 xx 10^(–5) , would a blue colour be shown by the electrolysed solution on addition of NH_3 ?
50mL of 0.1M CuSO_(4) solution is electrolysed with a current of 0.965A for a period of 200sec. The reactions at electrodes are: Cathode: Cu^(2+) +2e^(-) rarr Cu(s) Anode: 2H_(2)O rarr O_(2) +4H^(+) +4e . Assuming no change in volume during electrolysis, calculate the molar concentration of Cu^(2+),H^(+) and SO_(4)^(2-) at the end of electrolysis.
50 mL of 0.1 M CuSO_4 solution is electrolysed using Pt electrodes with a current of 0.965 ampere for a period of 1 minute. Assuming that volume of solution does not change during electrolysis, calculate [Cu^(2+)]. [H^+] and [SO_4^(2–)] after electrolysis. What will be the concentration of each species if current is passed using Cu electrodes ?
100mL of 0.5 M CuCO_4 (aq) solution was electrolysed using inert electrodes by passing current till the pH of the resulting solution was 2. The solution after electrolysis was Calculate the required volume (in mL) of Na_2SO_2O_3 :