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(E^(2))/(mu(0)) has the dimensions (E= e...

`(E^(2))/(mu_(0))` has the dimensions (`E=` electric field, `mu_(0)=` permeabililty of free space)

A

`[M^(2)L^(3)T^(-2)A^(2)]`

B

`[MLT^(-4)]`

C

`[ML^(3)T^(-2)]`

D

`[M^(-1)L^(2)TA^(-2)]`

Text Solution

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The correct Answer is:
B
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varepsilon_(0)E^(2) has the dimension of ( varepsilon_(0) = permittivity of free space, E = electric field)

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Knowledge Check

  • The dimensions of (B^(2)R^(2)C^(2))/(2mu_(0)) (Where B is magnetic filed, and mu_(0) is permeability of free space , R resistance and C is capacitance) is

    A
    `[ML^(-1)]`
    B
    `[MLT^(-1)]`
    C
    `[ML^(2)T^(-1)]`
    D
    `[MLT^(2)]`

  • If (A)/(mu_(0)) has the dimensions [MLT^(-4)] what is A?

    A
    square of electric flux
    B
    square of magnitic flux
    C
    square of electric field
    D
    square of energy

  • The dimensional formula for permeability of free space, mu_(0) is

    A
    `[MLT^(-2)A^(-2)]`
    B
    `[ML^(-1)T^(2)A^(-2)]`
    C
    `[ML^(-1)T^(-2)A^(2)]`
    D
    `[MLT^(-2)A^(-1)]`

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