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Determine the fractional change in volum...

Determine the fractional change in volume as the pressure of the atmosphere `(1.0xx10^(5)`Pa) around a metal block is reduced to zero by placing the block in vacuum. The bulk modulus for the block is `1.25xx10^(11) Nm^(-2)`.

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To determine the fractional change in volume of a metal block when the atmospheric pressure is reduced to zero (i.e., placed in a vacuum), we can use the concept of bulk modulus. Here’s a step-by-step solution: ### Step 1: Understand the Given Values - Initial atmospheric pressure, \( P = 1.0 \times 10^5 \, \text{Pa} \) - Bulk modulus of the block, \( K = 1.25 \times 10^{11} \, \text{N/m}^2 \) ### Step 2: Recall the Formula for Bulk Modulus The bulk modulus \( K \) is defined as: \[ K = \frac{\text{Stress}}{\text{Volumetric Strain}} \] Where: - Stress is the change in pressure, \( \Delta P \) - Volumetric strain is the fractional change in volume, \( \frac{\Delta V}{V} \) ### Step 3: Relate the Change in Pressure to the Bulk Modulus Since the block is placed in a vacuum, the change in pressure \( \Delta P \) is equal to the initial atmospheric pressure: \[ \Delta P = P = 1.0 \times 10^5 \, \text{Pa} \] ### Step 4: Express the Volumetric Strain From the definition of bulk modulus, we can rearrange the formula to express the volumetric strain: \[ \frac{\Delta V}{V} = \frac{\Delta P}{K} \] ### Step 5: Substitute the Values into the Formula Now, we can substitute the values of \( \Delta P \) and \( K \) into the equation: \[ \frac{\Delta V}{V} = \frac{1.0 \times 10^5 \, \text{Pa}}{1.25 \times 10^{11} \, \text{N/m}^2} \] ### Step 6: Calculate the Fractional Change in Volume Perform the calculation: \[ \frac{\Delta V}{V} = \frac{1.0 \times 10^5}{1.25 \times 10^{11}} = 8.0 \times 10^{-7} \] ### Final Answer The fractional change in volume of the metal block when the atmospheric pressure is reduced to zero is: \[ \frac{\Delta V}{V} = 8.0 \times 10^{-7} \] ---
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Knowledge Check

  • A metal block is experiencing an atmospheric pressure of 1 xx 10^(5)N//m^(2) , when the same block is placed vacuum chamber, the freactional change in its volume is (the bulk modulus of metal is 1.25 xx 10^(11) N//m^(2) )

    A
    `4 xx 10^(-7)`
    B
    `2 xx 10^(-7)`
    C
    `8 xx 10^(-7)`
    D
    `1 xx 10^(-7)`
  • The pressure required to reduce the given volume of water by 1% is, (Bulk modulus of water =2xx10^(9)N//m^(2) )

    A
    `2xx10^(7)N//m^(2)`
    B
    `2xx10^(8)N//m^(2)`
    C
    `2xx10^(10)N//m^(2)`
    D
    `2xx10^(10)N//m^(2)`
  • A spherical ball of volume 1000 cm^(3) is subjected to a pressure of 10 atomosphere. The change in volume is 10^(-2)cm^(-3) . IF the ball is made of iron find its bulk modulus. (Atmospheric pressure = 1xx10^(5) Nm^(-2) )

    A
    `1xx10^(11) N//m^(2)`
    B
    `2xx10^(11) N//m^(2)`
    C
    `3xx10^(11) N//m^(2)`
    D
    `4xx10^(11) N//m^(2)`
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