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A horizontal tube has different cross-se...

A horizontal tube has different cross-sectional areas at point A and B .The diameter of A is 4 cm and that of Bis 2 cm. Two manometer limbs are attached at A and B. When a liquid of density 8.0 g `cm^(-3)` flows through the tube, the pressure difference between the limbs of the manometer is 8 cm. Calculate the rate of flow of the liquid in the tube .

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Knowledge Check

  • The figure shown a pipe of uniform cross-section inclined in a vertical plane. A U-tube manometer is connected between the point A and B. If the liquid of density rho_(0) flows with velocity v_(0) in the pipe. Then the reading h of the manometer is

    A
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    B
    `h=(v_(0)^(2))/(2g)`
    C
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    D
    `h=(rho_(0) H)/(rho-rho_(0))`

  • A horizontal tube has different cross sections at points A and B . The areas of cross section are a_(1) and a_(2) respectively, and pressures at these points are p_(1)=rhogh_(1) and p_(2)=rhogh_(2) where rho is the density of liquid flowing in the tube and h_(1) and h_(2) are heights of liquid columns in vertical tubes connected at A and B . If h_(1)-h_(2)=h , then the flow rate of the liquid in the horizontal tube is

    A
    `a_(1)a_(2)sqrt((2gh)/(a_(1)^(2)-a_(2)^(2)))`
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    C
    `a_(1)a_(2)sqrt(((a_(1)^(2)+a_(2)^(2))h)/(2g(a_(1)^(2)-a_(2)^(2))))`
    D
    `(2a_(1)a_(2)gh)/sqrt(a_(1)^(2)-a_(2)^(2))`

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