If we take 2.2 g of `CO_2,` `6.02 xx 10^21` atoms of nitrogen and 0.03 gram atom of oxygen, then the molar ratio of C,N and O atom will be

Options

A. `1:2:5`
B. `5:1:3`
C. `5:1:2`
D. `2:5:3`

Explanation

To find the molar ratio of carbon (C), nitrogen (N), and oxygen (O) atoms from the given data, we can follow these steps:

### Step 1: Calculate the number of moles of CO₂
- Given mass of CO₂ = 2.2 g
- Molar mass of CO₂ = 12 (C) + 16 × 2 (O) = 44 g/mol
- Number of moles of CO₂ = mass / molar mass = 2.2 g / 44 g/mol = 0.05 moles

### Step 2: Determine the number of moles of nitrogen (N)
- Given number of nitrogen atoms = \(6.02 \times 10^{21}\)
- Avogadro's number = \(6.02 \times 10^{23}\) atoms/mole
- Number of moles of nitrogen = number of atoms / Avogadro's number = \(6.02 \times 10^{21} / 6.02 \times 10^{23} = 0.01\) moles

### Step 3: Determine the number of moles of oxygen (O)
- Given amount of oxygen = 0.03 gram atoms
- Since 1 gram atom is equivalent to 1 mole, the number of moles of oxygen = 0.03 moles

### Step 4: Find the molar ratio of C, N, and O
- From the calculations:
- Moles of C = Moles of CO₂ = 0.05
- Moles of N = 0.01
- Moles of O = 0.03
- The molar ratio of C:N:O = 0.05:0.01:0.03

### Step 5: Simplify the ratio
- To simplify, we can multiply each term by 100 to eliminate decimals:
- C = 0.05 × 100 = 5
- N = 0.01 × 100 = 1
- O = 0.03 × 100 = 3
- Therefore, the simplified ratio is 5:1:3.

### Final Answer
The molar ratio of C:N:O is **5:1:3**.

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