What is the total number of electrons present in 0.16 g of methane ?

Options

A. `6.023xx10^(22)`
B. 16
C. `12.04xx10^(23)`
D. `6.023xx10^(24)`

Explanation

To find the total number of electrons present in 0.16 g of methane (CH₄), we can follow these steps:

### Step 1: Calculate the Molecular Weight of Methane
The molecular formula of methane is CH₄.
- The atomic weight of Carbon (C) = 12 g/mol
- The atomic weight of Hydrogen (H) = 1 g/mol

Calculating the molecular weight of CH₄:
\[ \text{Molecular weight of CH₄} = 12 + (4 \times 1) = 12 + 4 = 16 \text{ g/mol} \]

### Step 2: Calculate the Number of Moles of Methane
Using the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molecular weight (g/mol)}} \]
Substituting the values:
\[ \text{Number of moles of CH₄} = \frac{0.16 \text{ g}}{16 \text{ g/mol}} = 0.01 \text{ moles} \]

### Step 3: Calculate the Number of Molecules of Methane
Using Avogadro's number (approximately \(6.022 \times 10^{23}\) molecules/mol):
\[ \text{Number of molecules} = \text{Number of moles} \times \text{Avogadro's number} \]
Substituting the values:
\[ \text{Number of molecules of CH₄} = 0.01 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mol} = 6.022 \times 10^{21} \text{ molecules} \]

### Step 4: Calculate the Number of Electrons in One Molecule of Methane
Each molecule of methane (CH₄) contains:
- 1 Carbon atom which has 6 electrons
- 4 Hydrogen atoms, each having 1 electron, contributing a total of 4 electrons

Thus, the total number of electrons in one molecule of CH₄:
\[ \text{Total electrons in one CH₄ molecule} = 6 + 4 = 10 \text{ electrons} \]

### Step 5: Calculate the Total Number of Electrons in 0.16 g of Methane
Now, to find the total number of electrons in all the molecules:
\[ \text{Total number of electrons} = \text{Number of molecules} \times \text{Electrons per molecule} \]
Substituting the values:
\[ \text{Total number of electrons} = 6.022 \times 10^{21} \text{ molecules} \times 10 \text{ electrons/molecule} = 6.022 \times 10^{22} \text{ electrons} \]

### Final Answer
The total number of electrons present in 0.16 g of methane is:
\[ \boxed{6.022 \times 10^{22}} \]