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About 5g of water at 30^(@)C and 5g of i...

About `5g` of water at `30^(@)C` and `5g` of ice at `-20^(@)C` are mixed together in a calorimeter. Calculate final temperature of the mixture. Water equivalent of the calorimeter is negligible. Specific heat of ice `=0.5"cal"g^(-1)C^(@)-1)` and latent heat of ice `=80"cal"g^(-1)`

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The correct Answer is:
`3.75 kg`
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5g of water at 30^@C and 5 g of ice at -29^@C are mixed together in a calorimeter. Find the final temperature of mixture. Water equivalent of calorimeter is negligible, specific heat of ice = 0.5 cal//g-^@C and latent heat of ice =80 cal//g .

5 g of water at 30^(@) C and 5 g of ice at -20^(@) C are mixed together in a caloritmeter. The water equivalent of calorimeter is negliglible and specific heat and latent heat of ice are 0.5 cal/ g^(@) C and 80 cal/g repsectively. The final temperature of the mixture is

Knowledge Check

  • 5 g of water at 30^@C and 5 g of ice at -20^@C are mixed together in a calorimeter Find the final temperature of the mixure. Assume water equivalent of calorimeter to be negligible, sp. Heats of ice and water are 0.5 and 1 cal//g C^@ , and latent heat of ice is 80 cal//g

    A
    `0^@C`
    B
    `10^@C`
    C
    `-30^@C`
    D
    `gt10^@C`

  • 19 g of water at 30^@C and 5 g of ice at -20^@C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice =0.5calg^(-1) (.^(@)C)^(-1) and latent heat of fusion of ice =80calg^(-1)

    A
    `0^@C`
    B
    `-5^@C`
    C
    `5^@C`
    D
    `10^@C`

  • The water equivalent of a copper calorimeter is 4.5g. If the specific heat of copper is 0.09 cal g^(-1).^(@)C^(-1) . Then

    A
    mass of the calorimeter is 0.5 kg
    B
    Thermal capacity of the calorimeter is 4.5 cal `cal^(@)C^(-1)`
    C
    heat requried to raise the temperature of the calorimter by `8^(@)C` will be 36 cal
    D
    heat required to melt 15 gm of ice placed in the calorimeter in equilibrium with ice, will be 1200 cal.

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