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In a process of current decay in an indu...

In a process of current decay in an inductor through a resistance, if in time t, current falls to `eta` times `(eta lt 1)` the initial value, find the time constant of circuit.

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Knowledge Check

  • When a choke coil carrying a steady current is short circuited, the current in it decreases to beta(lt1) times its initial value in a time T . The time constant of the choke coil is

    A
    `T/beta`
    B
    `T/(ln(1/beta)`
    C
    `T/(lnbeta)`
    D
    `T ln beta`

  • In an LR circuit, current at t=0 is 2A . After 2s it reduced to 18A. The time constant of the circuit is (in second)

    A
    `In((10)/(9))`
    B
    2
    C
    `(2)/(In((10)/(9)))`
    D
    `2In((10)/(9))`

  • A coil carrying a steady current is short-circuited. The current in it decreases alpha times in time t_(0) . The time constant of the circuit is

    A
    `tau = t_(0)` In `alpha`
    B
    `tau = (t_(0))/(In alpha)`
    C
    `tau = (t_(0))/(alpha)`
    D
    `tau = (t_(0))/(alpha - 1)`

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