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To avoid the precipitation of hydroxides...

To avoid the precipitation of hydroxides of `Ni^(2+),Co^(2+),Zn^(2+) and Mn^(2+)` along with those of `Fe^(3+),Al^(3+) and Cr^(3+)` the third group solution should be:

A

Heated with a few drops of conc. `HNO_(3)`

B

Treated with excess of `NH_(4)Cl`

C

`H_(2)S` gas is passed into solution

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
The value of `K_(sp)` of hydroxides of `Fe^(3+),Cr^(3+),Al^(3+)` are lower than that of `Co^(2+),Ni^(2+),Mn^(2+) and Zn^(2+)` Therefore, in the presence of `NH_(4)Cl`, dissociation of `NH_(4)OH` suppressed and conc. Of `OH^(-)`, furnished from `NH_(4)OH`, is such that only third roup basic radicals are precipitate.
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To avoid the precipitation of hydroxides of Ni^(2+),Co^(2+),Mn^(2+) along with those of the third group cations, the solutions should be:

Which of the following arrangements does not represent the correct order of the property stated against it ? (i) Ni^(2+) lt Co^(2+) lt Fe^(2+) lt Mn^(2+) : ionic size (ii) Co^(3+) lt Fe^(3+) lt Cr^(3+) lt Sc^(3+) : stability in aqueious solution (iii) Sc lt Ti lt Cr lt Mn : number of oxidation states (iv) V^(2+) lt Cr^(2+) lt Mn^(2+) lt Fe^(2+) : paramagnetic behaviour

which is are correct statement for following : Mn^(+4),Cr^(+2),Ni^(+2),Zn^(+2)

Of the ions Zn^(2), Ni^(2 +) and Cr^(3 +) [atomic number of Zn = 30, Ni = 28, Cr = 24 ]