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Calculated the Oxidation number of (i)...

Calculated the Oxidation number of
(i) iron in ` [Fe(CN)_6]^(4-) `
(ii) Cobalt in ` [Co(NH_3)_5Cl]^(2+)`

Text Solution

Verified by Experts

(i) In `[Fe(CN)_6]^(4-) ` Let the oxidation number of iron is x:
The net charges : ` 4=x +6(-1) =gt x=+2`
(ii) In ` [Co(NH_3) _5]^(2+) ,`let the oxidation number of cobalt is x:
The net charge :
` +2 =x+5(0) +1(-1) =gt x =+3`
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Knowledge Check

  • The oxidation number of Fe in Fe_(2) (SO_(4) )_(3) is

    A
    +2
    B
    +3
    C
    +1
    D
    0

  • What is the coordination number of Fe^(2+) in K_(4)[Fe(CN)_(6)] ?

    A
    `4`
    B
    `6`
    C
    `3`
    D
    `2`

  • The oxidation state of Fe in [Fe(CN)_(6)]^(4+) is…………………..

    A
    `II`
    B
    `III`
    C
    `VI`
    D
    `IV`

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    With the help of crystal field theory , product the number of unpaired electron in [Fe(CN)_6]^(-4) and [Fe(H_2O)_6]^(+2) complexes.

    The coordination number of cobalt in [CO(NH_(3))_(4)Cl_(2)]Cl is……… .

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