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The Ew of H(3) PO(4) in reaction is Ca...

The `Ew` of `H_(3) PO_(4)` in reaction is
`Ca(OH)_(2) + H_(3) PO_(4) rarr CaHPO_(4) + 2H_(2)O`
`(Ca = 40, P = 31, O = 16)`

Answer

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Explore conceptually related problems

Find out the equivalent weight of H_(3) PO_(4) in the reaction: Ca(OH)_(2) + H_(3) PO_(4) rarr CaHPO_(4) + 2 H_(2) O

What is the n-factor for H_(2)PO_(4) in the reaction 2NaOH+H_(3)PO_(4)rarr Na_(2)HPO_(4)+2H_(2)O ?

Knowledge Check

  • The Ew of H_(3)PO_(4) in the reaction is Ca(OH)_(2)+H_(3)PO_(4)rarrCaHPO_(4)+2H_(2)O (Ca = 40, P = 31, O = 16)

    A
    49
    B
    98
    C
    32.66
    D
    147

  • The equivalent weight of phosphoric acid (H_(3)PO_(4)) in the reaction NaOH+H_(3)PO_(4) rarr NaH_(2)PO_(4)+H_(2)O is

    A
    `25`
    B
    `98`
    C
    `59`
    D
    `49`

  • What is the equivalent weight of phosphoric acid (H_(3) PO_(4)) according to the equation NaOH + H_(3) PO_(4) rarr NaH_(2) PO_(4) + H_(2)O

    A
    `98 u`
    B
    `59 u`
    C
    `49 u`
    D
    `25 u`

    • Similar Questions

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    Find the equivalent weight of H_(3)PO_(4) in following rection H_(3)PO_(4)+OH^(-)rarrHPO_(4)^(2-)+H_(2)O

    The equivalent weight of phosphoric acid H_(3)PO_(4) in the reaction, NaOH+H_(3)PO_(4)rarrNaH_(2)PO_(4)+H_(2)O is:

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