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Two protons are a distance of 1 xx 10^(-...

Two protons are a distance of `1 xx 10^(-10) cm` from each other. The force acting on them are

A

nuclear force and gravitational force

B

nuclear force and coulomb force

C

coulomb force and gravitational force

D

nuclear, coulomb and gravitational force

Text Solution

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The correct Answer is:
To solve the problem of determining the forces acting on two protons that are a distance of \(1 \times 10^{-10} \, \text{cm}\) apart, we will analyze the types of forces that can act between them. ### Step-by-Step Solution: 1. **Convert the Distance to Meters:** \[ 1 \times 10^{-10} \, \text{cm} = 1 \times 10^{-12} \, \text{m} \] (Since \(1 \, \text{cm} = 10^{-2} \, \text{m}\), we multiply by \(10^{-2}\).) **Hint:** Always convert units to standard SI units for calculations. 2. **Identify the Types of Forces:** - **Gravitational Force:** Exists between any two masses, including protons. - **Electrostatic Force (Coulomb's Force):** Exists between charged particles, such as protons. - **Nuclear Force:** Acts between nucleons (protons and neutrons) at very short distances, typically on the order of \(10^{-15} \, \text{m}\). **Hint:** Remember the characteristics of different forces and their ranges. 3. **Determine the Applicability of Each Force:** - The distance \(1 \times 10^{-12} \, \text{m}\) is greater than \(10^{-15} \, \text{m}\), which means the nuclear force does not apply here. - Both the gravitational force and the electrostatic force are applicable at this distance. **Hint:** Compare the given distance with the known ranges of the forces. 4. **Calculate the Gravitational Force:** The gravitational force \(F_g\) between two protons can be calculated using Newton's law of gravitation: \[ F_g = \frac{G \cdot m_1 \cdot m_2}{r^2} \] where: - \(G \approx 6.674 \times 10^{-11} \, \text{N m}^2/\text{kg}^2\) (gravitational constant) - \(m_1 = m_2 = m_p \approx 1.67 \times 10^{-27} \, \text{kg}\) (mass of a proton) - \(r = 1 \times 10^{-12} \, \text{m}\) Plugging in the values: \[ F_g = \frac{(6.674 \times 10^{-11}) \cdot (1.67 \times 10^{-27})^2}{(1 \times 10^{-12})^2} \] **Hint:** Make sure to square the values correctly and keep track of units. 5. **Calculate the Electrostatic Force:** The electrostatic force \(F_e\) between two protons can be calculated using Coulomb's law: \[ F_e = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \] where: - \(k \approx 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2\) (Coulomb's constant) - \(q_1 = q_2 = e \approx 1.6 \times 10^{-19} \, \text{C}\) (charge of a proton) - \(r = 1 \times 10^{-12} \, \text{m}\) Plugging in the values: \[ F_e = \frac{(8.99 \times 10^9) \cdot (1.6 \times 10^{-19})^2}{(1 \times 10^{-12})^2} \] **Hint:** Ensure that you use the absolute values of the charges since we are interested in the magnitude of the force. 6. **Conclusion:** The forces acting on the two protons are the gravitational force and the electrostatic force. The nuclear force does not apply at this distance. **Final Answer:** The forces acting on the two protons are the **Coulombic force and the gravitational force**.
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